A) 1, 1-dicyano ethane
B) Ethyl cyanide
C) Vinyl cyanide
D) Divinyl cyanide
Correct Answer: C
Solution :
\[CH\equiv CH+HCN\xrightarrow{Ba{{(CN)}_{2}}}\underset{\text{Vinyl cyanide}}{\mathop{C{{H}_{2}}=CH-C\equiv N}}\,\]
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