A) Ethane
B) Acetylene
C) Ethylene
D) Methane
E) None of these
Correct Answer: B
Solution :
\[\underset{C{{H}_{2}}Br}{\overset{C{{H}_{2}}Br}{\mathop{|\,\,\,\,\,\,\,\,\,\,}}}\,+2KOH\text{ (alcoholic) }\xrightarrow{\Delta }CH\equiv CH+2KBr\]\[+2{{H}_{2}}O\]
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