A) \[HC\equiv CH+2HBr\to \]
B) \[C{{H}_{3}}C\equiv CH+2HBr\to \]
C) \[C{{H}_{3}}CH=C{{H}_{2}}+HBr\to \]
D) \[C{{H}_{3}}CH=CHBr+HBr\to \]
Correct Answer: B
Solution :
\[C{{H}_{3}}C\equiv CH+2HBr\xrightarrow{{}}\underset{Br}{\mathop{\underset{|}{\mathop{\overset{Br}{\mathop{\overset{|}{\mathop{C{{H}_{3}}-C-C{{H}_{3}}}}\,}}\,}}\,}}\,\]
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