A) \[CuCl/N{{H}_{4}}Cl\] and \[{{H}_{2}}/Pd(BaS{{O}_{4}})\]
B) \[N{{H}_{4}}Cl/CuCl\] and \[{{H}_{2}}/Pd(BaS{{O}_{4}})\]
C) \[{{H}_{2}}/Pd(BaS{{O}_{4}})\] and \[CuCl/N{{H}_{4}}Cl\]
D) \[{{H}_{2}}/Pd(BaS{{O}_{4}})\] and \[N{{H}_{4}}Cl/CuCl\]
Correct Answer: A
Solution :
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