A) Bromine water
B) Bayer's reagent
C) Fehling solution
D) Ammonical silver nitrate
Correct Answer: D
Solution :
\[\underset{\text{Propyne}}{\mathop{C{{H}_{3}}-C\equiv C-H}}\,\,+\underset{\text{Ammonical}}{\mathop{AgN{{O}_{3}}}}\,\to \underset{\begin{smallmatrix} \text{Siver}\,\text{salt}\,\text{of} \\ \,\,\,\text{Propyne} \end{smallmatrix}}{\mathop{C{{H}_{3}}-C\equiv C-Ag}}\,\]
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