A) Methane
B) Ethane
C) Acetylene
D) Ethylene
Correct Answer: C
Solution :
\[Ca{{C}_{2}}+2\,{{H}_{2}}O\to Ca\,{{\left( OH \right)}_{2}}+{{C}_{2}}{{H}_{2}}\] \[CH\equiv CH+2\,[Ag\,{{(N{{H}_{3}})}_{2}}]OH\to \] \[Ag\underset{\text{White}\,\text{ppt}\text{.}}{\mathop{-\,C\equiv C-}}\,Ag+4\,N{{H}_{3}}+2\,{{H}_{2}}O\]
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