A) Propane
B) Propene
C) Propyne
D) Propanol
Correct Answer: B
Solution :
\[\underset{n-\text{Propyl bromide}}{\mathop{C{{H}_{3}}-C{{H}_{2}}-C{{H}_{2}}-Br}}\,+KOH\xrightarrow{{{C}_{2}}{{H}_{5}}OH}\]\[\underset{\text{Propene}}{\mathop{C{{H}_{3}}-CH=C{{H}_{2}}}}\,+KBr+{{H}_{2}}O\]
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