A) \[C{{H}_{3}}-C{{H}_{2}}-C{{H}_{2}}-Br\]
B) \[C{{H}_{3}}-CHBr-C{{H}_{3}}\]
C) \[BrC{{H}_{2}}-CH=C{{H}_{2}}\]
D) \[C{{H}_{2}}=C=C{{H}_{2}}\]
Correct Answer: B
Solution :
\[C{{H}_{3}}-CH=C{{H}_{2}}+HBr\xrightarrow[\text{Markownikoff}\,\text{rule}]{}\]\[\underset{\text{2}-\text{Bromopropane}}{\mathop{C{{H}_{3}}-\underset{\underset{Br\,\,}{\mathop{|\,\,\,\,\,}}\,}{\mathop{CH}}\,-C{{H}_{3}}}}\,\]
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