A) \[R-C{{H}_{2}}-CHO\]
B) \[R-C{{H}_{2}}-C{{H}_{2}}-OH\]
C) \[\underset{O}{\mathop{\underset{||}{\mathop{R-C-C{{H}_{3}}}}\,}}\,\]
D) \[\underset{\,\,\,\,\,\,OH\,\,\,\,OH}{\mathop{\underset{\,\,|\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,|}{\mathop{R-CH-C{{H}_{3}}}}\,}}\,\]
Correct Answer: B
Solution :
\[3R-CH=C{{H}_{2}}+\frac{1}{2}{{B}_{2}}{{H}_{6}}\underset{\text{Ether}}{\mathop{\xrightarrow{\text{Dry}}}}\,\,{{(R-C{{H}_{2}}C{{H}_{2}})}_{3}}B\]\[\overset{\begin{matrix} {} \\ {} \\ \end{matrix}}{\mathop{\underset{\text{Alcohol}}{\mathop{3R-C{{H}_{2}}C{{H}_{2}}OH}}\,}}\,\]
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