A) Ethylene
B) Methane
C) Ethane
D) Acetylene
Correct Answer: A
Solution :
\[C{{H}_{2}}=C{{H}_{2}}+H\overset{-}{\mathop{O}}\,C\overset{+}{\mathop{l}}\,\to \underset{1-\text{Chloro-2-hydroxy ethane}}{\mathop{\underset{\underset{OH\,\,\,}{\mathop{\,\,\,|\,\,\,\,\,\,\,\,\,\,\,\,}}\,}{\mathop{\overset{2}{\mathop{C}}\,{{H}_{2}}}}\,-\underset{\underset{Cl\,\,\,\,\,\,}{\mathop{|\,\,\,\,\,\,\,\,\,\,}}\,}{\mathop{\overset{1}{\mathop{C}}\,{{H}_{2}}}}\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,}}\,\,\]
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