A) 1-propene
B) 2-propene
C) Isopropylene
D) All the three
Correct Answer: A
Solution :
\[C{{H}_{3}}C{{H}_{2}}C{{H}_{2}}Cl+KOH\to \]\[C{{H}_{3}}-CH=C{{H}_{2}}+KCl+{{H}_{2}}O\] \[\begin{array}{*{35}{l}} C{{H}_{3}}-\underset{|}{\mathop{C}}\,H-C{{H}_{3}}+KOH\to C{{H}_{3}}-CH=C{{H}_{2}}+KCl+{{H}_{2}}O \\ \ \ \ \ \ \ \ \ Cl \\ \end{array}\]You need to login to perform this action.
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