JEE Main & Advanced Chemistry Hydrocarbons / हाइड्रोकार्बन Question Bank Alkene

  • question_answer
    Ethylene is prepared by the dehydration of [CPMT 1974, 79; DPMT 1985; BHU 1989]

    A) Ethyl alcohol

    B) Methyl alcohol

    C) Acetic acid

    D) Oxalic acid

    Correct Answer: A

    Solution :

    \[C{{H}_{3}}-C{{H}_{2}}-OH\underset{\text{Dehydration}}{\mathop{\xrightarrow{\text{Conc}\text{. }{{H}_{2}}S{{O}_{4}}}}}\,C{{H}_{2}}=C{{H}_{2}}+{{H}_{2}}O\]


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