A) \[C{{H}_{4}}\]
B) \[{{C}_{2}}{{H}_{6}}\]
C) \[{{C}_{2}}{{H}_{4}}\]
D) \[{{C}_{2}}{{H}_{2}}\]
Correct Answer: C
Solution :
\[C{{H}_{3}}C{{H}_{2}}I+KOH\,(alc)\to C{{H}_{2}}=C{{H}_{2}}+KI+{{H}_{2}}O\] \[C{{H}_{2}}=C{{H}_{2}}+\underset{\begin{matrix} \, \\ \begin{matrix} \text{Alk}\text{. Pink} \\ {} \\ \end{matrix} \\ \end{matrix}}{\mathop{KMn{{O}_{4}}}}\,\xrightarrow{{{H}_{2}}O}\underset{\text{Colourless}\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,}{\mathop{\underset{OH\,}{\mathop{\underset{|\,\,\,\,\,\,\,}{\mathop{C{{H}_{2}}}}\,}}\,-\underset{OH\,}{\mathop{\underset{|\,\,\,\,\,\,\,}{\mathop{C{{H}_{2}}}}\,}}\,\,+Mn{{O}_{2}}}}\,\]
You need to login to perform this action.
You will be redirected in
3 sec
