A) Ethylene
B) Ethyne
C) Cyclobutane
D) Butane
Correct Answer: A
Solution :
\[\underset{Br\,\,}{\mathop{\underset{|\,\,\,\,\,\,\,}{\mathop{C{{H}_{2}}}}\,}}\,-\underset{Br\,\,\,}{\mathop{\underset{|\,\,\,\,\,\,\,\,}{\mathop{C{{H}_{2}}}}\,}}\,+Zn\to ZnB{{r}_{2}}+C{{H}_{2}}=C{{H}_{2}}\]
You need to login to perform this action.
You will be redirected in
3 sec
