A) Halogenation
B) Hydrogenation
C) Chlorination
D) Dehydro-halogenation
Correct Answer: D
Solution :
\[C{{H}_{3}}-\underset{\underset{Br\,}{\mathop{|\,\,\,\,}}\,}{\mathop{CH}}\,-C{{H}_{2}}-C{{H}_{3}}\xrightarrow{alc.\,KOH}\underset{\text{2-butene}}{\mathop{C{{H}_{3}}CH=CHC{{H}_{3}}}}\,\] The reaction is dehydrohalogenation.
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