A) 1, 2-dibromoethane
B) 1-bromo-2-chloroethane
C) Both A and B
D) 1, 1, 1-tribromoethane
Correct Answer: A
Solution :
\[C{{H}_{2}}=C{{H}_{2}}+B{{r}_{2}}\xrightarrow{CC{{l}_{4}}}\underset{\begin{smallmatrix} \text{1, 2-dibromo } \\ \text{ethane} \end{smallmatrix}}{\mathop{\underset{Br\,\,\,\,\,}{\mathop{\underset{|\,\,\,\,\,\,\,}{\mathop{C{{H}_{2}}}}\,}}\,-\underset{\underset{Br\,\,\,\,}{\mathop{|\,\,\,\,\,\,\,}}\,}{\mathop{C{{H}_{2}}}}\,}}\,\]
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