A) \[\underset{C{{H}_{3}}\,\,\,\,\,\,}{\mathop{\underset{|\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,}{\mathop{C{{H}_{3}}-CH-C{{H}_{2}}OH}}\,}}\,\] and \[C{{H}_{3}}C{{H}_{2}}MgBr\]
B) \[\underset{C{{H}_{3}}\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,}{\mathop{\underset{|\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,}{\mathop{C{{H}_{3}}-CH-C{{H}_{2}}-C{{H}_{2}}-C{{H}_{3}}}}\,}}\,\] and \[Mg(OH)Br\]
C) \[\underset{C{{H}_{3}}\,}{\mathop{\underset{|\,\,\,\,\,\,\,\,\,}{\mathop{C{{H}_{3}}-CH-C{{H}_{3}}}}\,}}\,\] and \[C{{H}_{3}}-C{{H}_{2}}OMgBr\]
D) \[\underset{C{{H}_{3}}}{\mathop{\underset{|\,\,\,\,\,\,}{\mathop{C{{H}_{3}}-CH-C{{H}_{3}}}}\,}}\,,C{{H}_{2}}=C{{H}_{2}}\] and \[Mg(OH)Br\]
Correct Answer: C
Solution :
\[C{{H}_{3}}-\underset{\underset{\,\,\,C{{H}_{3}}}{\mathop{|\,\,\,\,\,\,}}\,}{\mathop{CH}}\,-C{{H}_{2}}-\xrightarrow{{}}\]\[\underset{\text{Isobutane}}{\mathop{C{{H}_{3}}-\underset{C{{H}_{3}}}{\mathop{\underset{|\,\,\,\,\,\,\,}{\mathop{CH}}\,}}\,\,-C{{H}_{3}}}}\,\,\,+\underset{\begin{smallmatrix} \text{Ethoxy}\,\,\text{magnesium} \\ \,\,\,\,\,\,\,\,\,\,\text{bromide} \end{smallmatrix}}{\mathop{{{C}_{2}}{{H}_{5}}OMgBr}}\,\]
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