A) Zinc
B) Peroxides
C) \[Hg-Zn/HCl\]
D) All of these
Correct Answer: B
Solution :
\[C{{H}_{3}}-CH=C{{H}_{2}}+HBr\xrightarrow{\text{Markownikoffs rule}}\] \[\underset{2-\text{Bromopropane}}{\mathop{C{{H}_{3}}-\underset{\underset{Br\,\,}{\mathop{|\,\,\,\,\,\,}}\,}{\mathop{CH}}\,-C{{H}_{3}}}}\,+HBr\xrightarrow{\text{Presence of peroxide }}\] \[\underset{\text{1-Bromopropane }}{\mathop{C{{H}_{3}}-C{{H}_{2}}-C{{H}_{2}}-Br}}\,\]
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