A) \[{{H}_{2}}C=C{{H}_{2}}+{{C}_{6}}{{H}_{6}}\]
B) \[{{H}_{3}}C-C{{H}_{3}}+{{C}_{6}}{{H}_{6}}\]
C) \[{{H}_{3}}C-C{{H}_{2}}OH+{{C}_{6}}{{H}_{6}}\]
D) \[C{{H}_{3}}-CH=C{{H}_{2}}+{{C}_{6}}{{H}_{6}}\]
Correct Answer: A
Solution :
\[{{C}_{6}}{{H}_{6}}+{{H}_{2}}C=C{{H}_{2}}\underset{95{}^\circ \text{ pressure}}{\mathop{\xrightarrow{AlC{{l}_{3}}.Hl}}}\,{{C}_{6}}{{H}_{5}}C{{H}_{2}}C{{H}_{3}}\]
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