A) Ethylene glycol
B) Acetic acid
C) Ethane
D) Butyric acid
Correct Answer: A
Solution :
When ethylene is treated with cold alkaline \[KMnO4\], ethylene glycol is formed. \[\begin{matrix} H \\ H \\ \end{matrix}>C=C<\begin{matrix} H \\ H \\ \end{matrix}\underset{\text{Cold alkaline}}{\mathop{\xrightarrow{KMnO4}}}\,\underset{\text{Ethylene glycol}}{\mathop{\begin{matrix} H \\ H \\ \end{matrix}>\underset{OH}{\mathop{\ \underset{|}{\mathop{C}}\,-}}\,\underset{OH}{\mathop{\underset{|}{\mathop{C}}\,\ \ }}\,<\begin{matrix} H \\ H \\ \end{matrix}}}\,\]
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