A) 3-phenyl-2-propanol
B) 1-phenyl-2-propanol
C) 2-phenyl-2-propanol
D) 2-phenyl-1-propanol
Correct Answer: C
Solution :
\[C{{H}_{3}}-\overset{Ph}{\mathop{\overset{|}{\mathop{C}}\,=}}\,C{{H}_{2}}\xrightarrow{{{H}_{3}}{{O}^{+}}}C{{H}_{3}}-\underset{OH}{\overset{Ph}{\mathop{\underset{|}{\overset{|}{\mathop{C}}}\,-}}}\,C{{H}_{3}}\]
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