A) \[{{H}_{2}}C=CH-C\equiv CH\]
B) \[HC\equiv C-C\equiv CH\]
C) \[{{H}_{2}}C=C=C=C{{H}_{2}}\]
D)
Correct Answer: A
Solution :
\[\overset{s{{p}^{2}}\,\,\,\,}{\mathop{C{{H}_{2}}}}\,=\overset{s{{p}^{2}}}{\mathop{CH}}\,-\overset{sp}{\mathop{C}}\,\equiv \overset{sp\,\,\,}{\mathop{CH}}\,\]
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