A) \[\underset{C{{H}_{3}}\,OH}{\mathop{\underset{|\,\,\,\,\,\,\,\,\,\,\,\,\,\,|\,\,\,\,\,}{\mathop{\overset{C{{H}_{2}}\,\,\,\,\,}{\mathop{\overset{\,|\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,}{\mathop{C{{H}_{3}}-C-CH-C{{H}_{2}}}}\,}}\,}}\,}}\,\]
B) \[\underset{C{{H}_{3}}\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,}{\mathop{\underset{|\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,}{\mathop{\overset{\,\,C{{H}_{3}}\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,}{\mathop{\overset{\,|\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,}{\mathop{C{{H}_{3}}-C-C{{H}_{2}}-C{{H}_{2}}OH}}\,}}\,}}\,}}\,\]
C) \[\underset{C{{H}_{3}}\,\,\,\,\,\,\,}{\mathop{\underset{|\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,}{\mathop{\overset{\,\,OH\,C{{H}_{3}}}{\mathop{\overset{\,|\,\,\,\,\,\,\,\,\,\,\,\,\,|\,\,\,\,\,\,}{\mathop{C{{H}_{3}}-C-CH-C{{H}_{3}}}}\,}}\,}}\,}}\,\]
D) \[\underset{C{{H}_{3}}\,}{\mathop{\underset{|\,\,\,\,\,\,\,\,\,\,}{\mathop{\overset{\,\,C{{H}_{3}}\,}{\mathop{\overset{\,|\,\,\,\,\,\,\,\,\,\,\,}{\mathop{HOC{{H}_{2}}-C-C{{H}_{2}}-C{{H}_{2}}}}\,}}\,}}\,}}\,\]
Correct Answer: A
Solution :
\[C{{H}_{3}}-\underset{\underset{C{{H}_{3}}}{\mathop{|\,\,\,\,\,\,\,\,\,}}\,}{\overset{\overset{C{{H}_{3}}}{\mathop{|\,\,\,\,\,\,\,\,\,}}\,}{\mathop{\,C-C}}}\,H=C{{H}_{2}}\underset{\,\,\,\,\,\,\,\,ii)\,\,NaB{{H}_{4}}\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,}{\mathop{\xrightarrow{\,I)\,Hg\,{{(OAc)}_{2}};\,{{H}_{2}}O}}}\,\] \[C{{H}_{3}}-\underset{\underset{\,C{{H}_{3}}}{\mathop{|\,\,\,\,\,\,\,\,}}\,}{\overset{\overset{C{{H}_{3}}}{\mathop{|\,\,\,\,\,\,\,\,}}\,}{\mathop{\,C\,\,\,\,-\,}}}\,\underset{\underset{OH}{\mathop{|\,\,\,\,\,}}\,}{\mathop{CH}}\,-C{{H}_{3}}\]
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