A) Propyne
B) Propene
C) Propanol
D) Propane
Correct Answer: B
Solution :
\[C{{H}_{3}}-C{{H}_{2}}-C{{H}_{2}}-OH\xrightarrow{PC{{l}_{3}}}\] \[\underset{\text{propylchloride}}{\mathop{\underset{\text{(a)}}{\mathop{C{{H}_{3}}-C{{H}_{2}}-C{{H}_{2}}-Cl}}\,}}\,\xrightarrow{\text{Alc}\text{. }KOH}\underset{\Pr opene}{\mathop{\underset{\text{(b)}}{\mathop{C{{H}_{3}}-CH=C{{H}_{2}}}}\,}}\,\]
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