A) \[C{{H}_{2}}Cl.CH=C{{H}_{2}}\]
B) \[C{{H}_{3}}.CHCl.C{{H}_{2}}Cl\]
C) \[C{{H}_{2}}Cl.CHCl.C{{H}_{2}}Cl\]
D) All the three
Correct Answer: A
Solution :
\[C{{H}_{3}}-CH=C{{H}_{2}}+C{{l}_{2}}\xrightarrow{{{500}^{o}}C}\]\[\underset{\underset{Cl\,\,\,}{\mathop{|\,\,\,\,\,\,\,\,}}\,}{\mathop{C{{H}_{2}}}}\,-CH=C{{H}_{2}}+HCl\] This reaction is called allylic halogenation reaction because halogenation occurs at the allylic position of an alkene
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