A) Chlorine
B) Bromine
C) Iodine
D) All equal
Correct Answer: A
Solution :
\[{{C}_{2}}{{H}_{4}}+C{{l}_{2}}\,\,\xrightarrow{CC{{l}_{4}}}\underset{\text{Ethelene Chloride}}{\mathop{Cl-C{{H}_{2}}-C{{H}_{2}}-Cl}}\,\]
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