A) 1-butene
B) 2-butene
C) 1-butanol
D) 2-butanol
Correct Answer: A
Solution :
\[ClC{{H}_{2}}-C{{H}_{2}}-C{{H}_{2}}-C{{H}_{3}}\xrightarrow{alc.\,KOH}\] \[\underset{\text{1}-\text{butene}}{\mathop{C{{H}_{2}}=CH-C{{H}_{2}}-C{{H}_{3}}}}\,\]
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