A) Carbon and \[{{H}_{2}}\]
B) Polyethylene
C) Acetylene and \[{{H}_{2}}\]
D) None of these
Correct Answer: B
Solution :
\[\underset{\text{(ethylene)}}{\mathop{n\,(C{{H}_{2}}=C{{H}_{2}})}}\,\underset{\text{high pressure}}{\mathop{\xrightarrow{{{400}^{o}}C}}}\,\,\,\underset{\text{(polyethylene)}}{\mathop{{{(-C{{H}_{2}}-C{{H}_{2}}-)}_{n}}}}\,\]
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