A) Ethyl alcohol
B) Acetaldehyde
C) Acetic acid
D) Ethylene glycol
Correct Answer: D
Solution :
\[\underset{\text{Ethene}}{\mathop{C{{H}_{2}}=C{{H}_{2}}}}\,\xrightarrow{\text{Cold}\text{.alk}\text{.}\,KMn{{O}_{4}}}\underset{\text{Ethylene}\,\text{glycol}}{\mathop{\underset{OH}{\mathop{\underset{|\,\,\,\,\,\,}{\mathop{C{{H}_{2}}}}\,}}\,-\underset{OH\,}{\mathop{\underset{|\,\,\,\,\,\,\,}{\mathop{C{{H}_{2}}}}\,}}\,}}\,\]
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