A) Butene-1
B) Butene-2
C) Butane
D) Butyne-1
Correct Answer: B
Solution :
\[C{{H}_{3}}-\overset{\overset{Br\,\,}{\mathop{|\,\,\,\,\,}}\,}{\mathop{CH}}\,-C{{H}_{2}}-C{{H}_{3}}+\underset{\left( \text{alc} \right)}{\mathop{KOH}}\,\to \] \[\underset{\text{Butene-2}}{\mathop{C{{H}_{3}}-CH=CH-C{{H}_{3}}}}\,+KBr+{{H}_{2}}O\]You need to login to perform this action.
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