JEE Main & Advanced Chemistry Hydrocarbons / हाइड्रोकार्बन Question Bank Alkene

  • question_answer
    The final product formed when ethyl bromide is treated with excess of alcoholic KOH is [MP PET 1999]

    A) Ethylene

    B) Ethane

    C) Ethyne

    D) Vinyl bromide

    Correct Answer: A

    Solution :

    \[C{{H}_{3}}-C{{H}_{2}}-Br+KOH\to C{{H}_{2}}=C{{H}_{2}}+KBr+{{H}_{2}}O\]


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