A) \[C{{H}_{3}}C{{H}_{2}}Cl\] and NaOH
B) \[C{{H}_{2}}Cl-C{{H}_{2}}OH\] and \[\text{aq}\text{. }NaHC{{O}_{3}}\]
C) \[C{{H}_{3}}C{{H}_{2}}OH\] and HCl
D) \[C{{H}_{2}}=C{{H}_{2}}\] and heat
Correct Answer: B
Solution :
\[C{{H}_{2}}=C{{H}_{2}}\xrightarrow{HOCl}\underset{\underset{Cl\,\,\,\,\,}{\mathop{|\,\,\,\,\,\,\,\,}}\,}{\mathop{C{{H}_{2}}}}\,-\underset{\underset{OH\,\,}{\mathop{|\,\,\,\,\,\,\,\,}}\,}{\mathop{C{{H}_{2}}}}\,\xrightarrow{aq\,NaHC{{O}_{3}}}\] \[\underset{\text{Glycol}}{\mathop{\underset{\underset{C{{H}_{2}}-OH}{\mathop{|\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,}}\,}{\mathop{C{{H}_{2}}-OH}}\,}}\,\]
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