A) 1-butene
B) 2-butene
C) n-butane
D) Isobutane
Correct Answer: C
Solution :
\[\underset{n-\text{Butane}}{\mathop{C{{H}_{3}}C{{H}_{2}}C{{H}_{2}}C{{H}_{3}}}}\,\xrightarrow{\text{Cracking}}\]\[C{{H}_{4}}+C{{H}_{3}}-CH=C{{H}_{2}}\]
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