A) Acetic acid
B) Acetamide
C) Potassium acetate
D) Ethyl acetate
Correct Answer: C
Solution :
\[\underset{\text{Potassium acetate}}{\mathop{2C{{H}_{3}}COOK}}\,+2{{H}_{2}}O\xrightarrow{\text{Electrolysis}}\]\[\underset{\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\text{Anode}}{\mathop{C{{H}_{3}}-C{{H}_{3}}+2C{{O}_{2}}}}\,+\underset{\,\,\,\,\,\,\,\,\,\,\,\,\text{Cathode}}{\mathop{2KOH+{{H}_{2}}}}\,\]
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