A) n-pentane
B) Neopentane
C) Isopentane
D) n-butane
Correct Answer: B
Solution :
\[C{{H}_{3}}-\underset{\underset{C{{H}_{3}}}{\mathop{|\,\,\,\,\,\,\,}}\,\,\,\,\,\,\,\,\,\,\,}{\overset{\overset{C{{H}_{3}}}{\mathop{|\,\,\,\,\,\,\,}}\,\,\,\,\,\,\,\,\,\,\,\,}{\mathop{C-C{{H}_{3}}}}}\,\] Replaceable hydrogen atoms are present only on 4 primary carbon atoms. Hence, it gives only are monochloro Substituted product.
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