A) \[{{C}_{2}}{{H}_{4}}\]
B) \[C{{H}_{3}}O\]
C) \[C{{H}_{3}}Br\]
D) \[C{{H}_{3}}C{{H}_{2}}OH\]
Correct Answer: C
Solution :
\[C{{H}_{3}}Br+{{H}_{2}}\] \[\xrightarrow{LiAl{{H}_{4}}}\]\[C{{H}_{4}}\](methane) \[\xrightarrow{Na}C{{H}_{3}}-C{{H}_{3}}\](Ethane)
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