A) sp
B) \[s{{p}^{2}}\]
C) \[s{{p}^{3}}\]
D) \[s{{p}^{3}}d\]
Correct Answer: B
Solution :
\[H-\underset{H\,}{\mathop{\underset{|\,\,\,\,}{\mathop{\overset{s{{p}^{2}}}{\mathop{C\,\,}}\,}}\,}}\,=\,\underset{H\,\,}{\mathop{\underset{|\,\,\,\,}{\mathop{\overset{s{{p}^{2}}}{\mathop{C\,-}}\,}}\,}}\,H\] \[s{{p}^{2}}\]-hybridisation (trigonal planar).
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