A) Methane
B) Ethane
C) Ethene
D) Ethyne
Correct Answer: A
Solution :
\[A{{l}_{4}}{{C}_{3}}+6{{H}_{2}}O\to \underset{\text{Methane}}{\mathop{3C{{H}_{4}}}}\,+2A{{l}_{2}}{{O}_{3}}\]
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