A) \[\underset{C{{H}_{3}}}{\mathop{\underset{|\,\,\,\,\,\,\,}{\mathop{C{{H}_{3}}-C{{H}_{2}}-CH-C{{H}_{2}}-C{{H}_{3}}}}\,}}\,\]
B) \[\overset{\,\,C{{H}_{3}}}{\mathop{\overset{|\,\,\,\,\,\,\,}{\mathop{C{{H}_{2}}=CH-CH-C{{H}_{2}}-C{{H}_{3}}}}\,}}\,\]
C) \[\underset{C{{H}_{3}}}{\mathop{\underset{|\,\,\,\,\,\,\,}{\mathop{C{{H}_{3}}-CHI-CH-C{{H}_{2}}-C{{H}_{3}}}}\,}}\,\]
D) \[\underset{C{{H}_{3}}}{\mathop{\underset{|\,\,\,\,\,\,\,}{\mathop{C{{H}_{2}}=CH-C(I)-C{{H}_{2}}-C{{H}_{3}}}}\,}}\,\]
Correct Answer: A
Solution :
\[\underset{\text{2,3}-\text{dibromo}-\text{3}-\text{methyl}\,\text{pentane}\,\,\,\,\,\,\,\,\,\,}{\mathop{C{{H}_{3}}-\underset{\underset{Br\,\,}{\mathop{\,|\,\,\,\,\,}}\,}{\mathop{CH}}\,-\underset{\underset{Br}{\mathop{|\,\,}}\,\,\,\,\,}{\overset{\overset{C{{H}_{3}}}{\mathop{|\,\,\,\,\,\,\,}}\,}{\mathop{C-}}}\,C{{H}_{2}}-C{{H}_{3}}+Zn\to }}\,\] \[\underset{\text{HI}\,+\,{{\,}_{\downarrow }}\,\,\,\text{Red}\,\text{P}\,\left( \text{Reduction} \right)}{\mathop{C{{H}_{3}}-CH=\overset{\overset{C{{H}_{3}}}{\mathop{|\,\,\,\,\,\,\,\,}}\,}{\mathop{C\,-\,\,}}\,C{{H}_{2}}-C{{H}_{3}}+ZnB{{r}_{2}}}}\,\] \[\underset{\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\text{3}-\text{Methyl}\,\text{pentane}}{\mathop{C{{H}_{3}}-C{{H}_{2}}-\underset{\underset{C{{H}_{3}}}{\mathop{|\,\,\,\,\,\,\,\,}}\,}{\mathop{CH\,\,}}\,-C{{H}_{2}}-C{{H}_{3}}}}\,\]
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