A) \[C{{H}_{4}}\]
B) \[{{C}_{2}}{{H}_{4}}\]
C) \[{{C}_{6}}{{H}_{6}}\]
D) \[{{C}_{2}}{{H}_{2}}\]
Correct Answer: A
Solution :
% of hydrogen = \[\frac{\text{Mass of hydrogen}}{\text{Mass of compound}}\ \times \ 100\] \[C{{H}_{4}}=\frac{4}{16}\ \times \ 100\ =\ 25%\].
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