A) \[C{{H}_{4}}\]
B) \[{{C}_{2}}{{H}_{6}}\]
C) \[{{C}_{3}}{{H}_{8}}\]
D) \[{{C}_{4}}{{H}_{10}}\]
Correct Answer: A
Solution :
It is not possible to prepare \[C{{H}_{4}}\] by wurtz reaction.
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