A) Reaction of \[C{{H}_{3}}I\] with Na in ether
B) Reaction of sodium acetate with sodalime
C) Electrolysis of concentrated sodium acetate solution
D) Reaction of ethyl chloride with alco. KOH
Correct Answer: D
Solution :
\[C{{H}_{3}}-C{{H}_{2}}-Cl+\underset{\text{(alc}\text{.)}}{\mathop{KOH}}\,\to \underset{\text{Ethene}}{\mathop{C{{H}_{2}}=C{{H}_{2}}}}\,+KCl+{{H}_{2}}O\] In presence of alc. KOH dehydrohalogenation occur and alkene is formed.
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