A) \[C{{H}_{3}}C{{H}_{2}}C{{H}_{2}}Cl\underset{{{H}_{2}}O}{\mathop{\xrightarrow{Mg/\text{ether}}}}\,\]
B) \[C{{H}_{3}}COCl\underset{{{H}_{2}}O}{\mathop{\xrightarrow{C{{H}_{3}}MgX}}}\,\]
C) \[C{{H}_{3}}CH=C{{H}_{2}}\underset{C{{H}_{3}}COOH}{\mathop{\xrightarrow{{{B}_{2}}{{H}_{6}}}}}\,\]
D) \[\underset{OH\,\,\,\,}{\mathop{\underset{|\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,}{\mathop{C{{H}_{3}}CH-C{{H}_{3}}}}\,}}\,\xrightarrow{P/HI}\]
Correct Answer: B
Solution :
With calculated amount of Grignard reagent, acetyl chloride forms ketones. \[C{{H}_{3}}COCl+XMgC{{H}_{3}}\to C{{H}_{3}}COC{{H}_{3}}+Mg<\begin{matrix} Cl \\ X \\ \end{matrix}\]
You need to login to perform this action.
You will be redirected in
3 sec
