A) n-propyl bromide
B) Ethyl bromide and n-butyl bromide
C) Ethyl chloride and n-butyl chloride
D) Methyl bromide and n -pentyl chloride
Correct Answer: A
Solution :
According to wurtz reaction. \[2C{{H}_{3}}C{{H}_{2}}C{{H}_{2}}Br+2Na\xrightarrow{\text{ether}}\]\[C{{H}_{3}}{{(C{{H}_{2}})}_{4}}C{{H}_{3}}+2NaBr\]
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