A) \[KCl\]
B) \[NaCl\]
C) \[N{{H}_{4}}Cl\]
D) \[BaS{{O}_{4}}\]
Correct Answer: D
Solution :
\[BaS{{O}_{4}}\] is sparingly soluble in water because the solubility of second group sulphates decreases with increasing atomic size. Because of hydration energy decreases.
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