• # question_answer $Sn$ is dissolved in excess of $NaOH$ solution, the compound obtained is [RPMT 1997] A) $Sn{{(OH)}_{2}}$ B) $N{{a}_{2}}Sn{{O}_{3}}$ C) $N{{a}_{2}}Sn{{O}_{2}}$ D) $Sn{{O}_{2}}$

$Sn+2NaOH+{{H}_{2}}O\to N{{a}_{2}}Sn{{O}_{3}}+2{{H}_{2}}$