• # question_answer When $NaOH$ is prepared, the gas released is [CPMT 1996] A) $C{{l}_{2}}$ B) ${{H}_{2}}$ C) ${{O}_{2}}$ D) ${{H}_{2}}O$

Correct Answer: A

Solution :

$2NaCl+2{{H}_{2}}O\to 2NaOH+\underset{\text{Anode}}{\mathop{C{{l}_{2}}}}\,+\underset{\text{Cathode}}{\mathop{{{H}_{2}}}}\,$

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