A) \[2{{t}^{2}}+\frac{2}{{{t}^{2}}}+4t=0\]
B) 4
C) \[4t+4=0\]
D) \[2t+2=0\]
Correct Answer: C
Solution :
(c) \[{{\left( t+\frac{1}{t} \right)}^{2}}-{{\left( t-\frac{1}{t} \right)}^{2}}=4\](we have done such expansions earlier and this result may be committed to memory) \[\therefore \]\[{{\left( t+\frac{1}{t} \right)}^{2}}-{{\left( t-\frac{1}{t} \right)}^{2}}+4t=0\] \[\Rightarrow \]\[4+4t=0\]
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