A) \[2n-1\]
B) \[4n+3\]
C) \[4n+1\]
D) \[{{n}^{2}}-1\]
Correct Answer: B
Solution :
These problems are solved by observations. \[{{T}_{1}}=7,\,\,{{T}_{2}}=11,\,\,{{T}_{3}}=15\Rightarrow \]Regular difference of 4. For \[n=1:{{T}_{1}}=4\times 1+3=7,\,3;{{T}_{2}}=4\times 2+3=11\]and so on.
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