A) 1
B) 0
C) \[-1\]
D) 2
Correct Answer: B
Solution :
(b): \[{{\left( x+\frac{1}{x} \right)}^{2}}\Rightarrow x+\frac{1}{x}=\sqrt{3}\] \[{{\left( x+\frac{1}{x} \right)}^{3}}\Rightarrow {{x}^{3}}+\frac{1}{{{x}^{3}}}+3\times x\times \frac{1}{x}\left( x+\frac{1}{x} \right)\] \[\Rightarrow 3\sqrt{3}={{x}^{3}}\frac{1}{{{x}^{3}}}+3\times 1\times \sqrt{3}\] \[\Rightarrow 0={{x}^{3}}\frac{1}{{{x}^{3}}}\].
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